(2x+5)^2-x(4x-5)=100

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Solution for (2x+5)^2-x(4x-5)=100 equation: 



(2x+5)^2-x(4x-5)=100

We move all terms to the left:

(2x+5)^2-x(4x-5)-(100)=0

We multiply parentheses

-4x^2+(2x+5)^2+5x-100=0

We add all the numbers together, and all the variables

-4x^2+5x+(2x+5)^2-100=0

We move all terms containing x to the left, all other terms to the right

-4x^2+5x+(2x+5)^2=100

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